原问题
How could we have initialized
myphonebook
so that it would accept integers as values?
myphonebook = Dict(“Jenny” => “867-5309”, “Ghostbusters” => “555-2368”)
原问题
How could we have initialized
myphonebook
so that it would accept integers as values?
myphonebook = Dict(“Jenny” => “867-5309”, “Ghostbusters” => “555-2368”)
julia> myphonebook = Dict("Jenny" => "867-5309", "Ghostbusters" => "555-2368")
Dict{String,String} with 2 entries:
"Jenny" => "867-5309"
"Ghostbusters" => "555-2368"
没太懂,你这样初始化就会得到 Dict{String,String}
。
你是想要能这样 myphonebook["Jenny"] = 8675309
赋值?
可以弄个函数用来读写 myphonebook
,在函数里转换一下输入。让它做合法性检验,再把整数转成字符串,也可以顺带加上 -
.
flexible_phonebook=Dict("Jenny"=>8675309,"Ghostbusters"=>"555-2368"
实际上,这个问题是接上面的,上面能接受整数类型,现在想让
myphonebook = Dict("Jenny" => "867-5309", "Ghostbusters" => "555-2368")
也接受整数类型,不知应该怎么弄,这里还没讲到函数,应该可以不用函数
那就不给初始值,也就是都设为 Any
julia> myphonebook = Dict()
Dict{Any,Any} with 0 entries
julia> myphonebook["Jenny"] = 8675309
8675309
julia> myphonebook["Ghostbusters"] = "555-2368"
"555-2368"
julia> myphonebook
Dict{Any,Any} with 2 entries:
"Jenny" => 8675309
"Ghostbusters" => "555-2368"
julia> myphonebook["Jenny"] = "8675309"
"8675309"
julia> myphonebook
Dict{Any,Any} with 2 entries:
"Jenny" => "8675309"
"Ghostbusters" => "555-2368"
newmyphonebook = convert(Dict{String, Any}, myphonebook)
newmyphonebook[“Shi”] = 123456
是的 我解决了 还有一种方法是
myphonebook = Dict{String, Any}("Jenny" => "867-5309", "Ghostbusters" => "555-2368")
知道了 谢谢 才发现原来习题是有答案的